初一10道数0计算学题及答案 1.2×58+10（=1.25×）+81.2×51=010+2.1522=.5913-2123（+88）.=913-12238-.8=900-8.808991.=1.24×82.3+8.×3176.8=.3（×124+..71)=86.×3324.=9999×91001=9999×10（0+01）=999×1009+999091×=1008999014.8×63-..6×36.＋5.38×.73=（4.816-5.）6.×3＋.3×8.73=.8×363.8.+×337..83×（.6＋337）.=83×1.08=312.+4.780+87.6=（.1248+76.）0.7+8=1 +0.7801=0.78933-157-34933=-（51+437=9）3-200=3733481-9928=421-180002+3823=3I×221×525=48×125××52（4×25=×（）8×15）21=0×0010=10000090048÷286=（6002+6200+260+01284）÷62=602÷206+20062÷6+2600÷62+218÷2694=10+1000+100+48=342888143÷=（1290+591）1÷443=120÷93+15491÷43 ×87分之4÷1[(÷.3-22.5)]=8×497÷/[÷0125].8=4/×7÷48/7=2700×506（－499）÷900=70207×÷9001890=0÷900=231302.（－418.－49085.）÷25.=3302－5..5752÷5.33.=202－302.=011÷（1－1）÷.15（=1－）÷1.51=05.÷10=18.1＋（－3.092÷0.92）31×=18.＋117×.1=8.1＋117.1=98[.1-8+29]+-[5]+620=1[-9]3+[-2+[]-]+10+1+=-23 [3-0]11+52+310+[-75=]50[-1+[-1/2]]+/34[-+/1]4=-1[7/-2+]/6+[5-.5]+0/5419+/=1625.-26[54.+[]-614.]+8154.+61.=481.-12+5[-715]+/-1[8]+[-/.0]=6-3-98[+6+(-87)]*732[65+-7()5(-)7-](84++)35+21*/8-6-5296821-8/-1*81+16-/9-7/9256-.6-4(3/4-+16-4.3-/)4/2+31+56/7/-1[2/324-1-4/(-0.4)*]1//+3222(-4++)-2)(4+3*-28*8-1/*28+1//(823+/12//()1-/21*)(-2)1(2-8/()6-4)++-1)2/(-()+207/(--8*(-2)(1)4/5-6+/1/+2/3)31/2/8-16(/3-*)-2()(5+/3*883/0/-()23(--48/2*)(3)-/-(6)1/*2-(41/5)2//3- x32y-5+-x7143y727×＋7256×〔73-（52+18）1〕15÷2601÷〔8（37-）×18〕9208840÷2＋4×352÷135×(266－25)085(×95－441÷02)58480÷7(015＋202)14×3×77＋27×253684321÷1(×32＋785)37.8[-（7.855+.64）]×30561[×17.7-7.(2÷)3]947（－99）576＋64×63(913×276－2÷)3[19－（54＋238）×6][7（71-5.6.）0.9-1×1.5÷2].58134÷21(×35＋7825.4)÷[.26（×37-..2）+0962]（9.7－459）9＋67×664－(09.＋258.)9÷].1802.818÷.43－0.24×0352.0×[2(4.－4.81÷)0.＋04.152]-(8.3412.52.×)408.〔15×.5(-.2135.79〕（31)8..324）×÷194－546.81÷8.×.0936.72÷4.259×9.3.416÷（0.10635×）08×.(1[06－.6)7÷12.]136+（46×）（6-5453÷23）6.(-86.×8.055÷)850.12.×.840÷12.4×8.（58+73÷（）6-9×45 8）2-100÷（97+1311）（3.2××.5+215）÷.16.8+51×41（4+20÷26）820-16×4÷1383+（524+18）6×（5128-208÷18）.729×1.-16830.÷5477/[÷1/3×（35/3/1-0）]（4/5+1/4÷）7/+7/3011278－.0（÷1.3＋416.56）37.182700-（9÷+31×1）1（31+646）×（6-535÷432）3.×21（.52+.5÷1.）65+18×（414+2802÷）（65+837）÷（649×5-）6(8-.68×0..55)÷8.5（842+1）×（615-22808÷81）.1024.8÷×012×.4.8（3.21×5+2..5÷）1.621-3604×1÷8+35101.5-1.05×70.-547.58×.（.37-80.1）3+4.×32.4374+47×2-5416052÷235.2-（+69.278÷3.2×）25.8（58+737）（÷6-4×95）[（.71-5.6）×0.9-
1.51]2÷5（.3.2×15+..52÷）165.4÷.[26.（×.37-2.9）0+6.212]6×÷ （127.2--6）3.2×+（61.52.5）+1÷6.3.2×（15.2.+）÷15.6.58（×.87-30.3）1+4.23×74.3302.－14（84.90－.5）82.51)÷2+3(-37(2))(-48+)-49)(()73(+2-04).(4).23+4(-.57)(5)7-(73)+(/7-6)/()9/4+6-3(2)/7()375.+2.2()55+4(/)-837.5(+5/+4)(-+.5)1(9()-1/74+)-10/3()(++1/3)+(131/)3(10)(-1.)8++(02)+.-1(7.)(0+1)+(.+18.+(+1.))411)(+(.13)-+17(/)(71)2-(2)(-+/32(13))(-|72)-.(-.36+()11)|(14.)|(5/-)4--3(/)4-|1|-5/-4-|34/)|(5)1-(/2199*)-(7/63/2-+/38()6)41a*)(-b3*)5c)(*16/1 .3/7×9/494/-32.8/×915/36+1/723.2×15/6–2/93×48.×/45+14/5.÷6/38–3/86÷6.4/75/×9+37/×59/75/2.（-/3+2/4）85.7/8+（1/8+/199.）9×56/5+/61.3/4×0/981/3-0.21＋χ1.8×.90=72.9(5－χ)0×3.1.=0264.χχ-28=4+41.17.5×4/9+/3412.16×（1/2+23）/138.×4/5+811/51×.4315/6–×5/615.9/7-2/7（–10/12）6.159/×811–42×71/7.4/×55/261+23/×/418.1438×7/–/56×1/2151.91/37–234/×924/203.×2/9+13/ 2.15/7×3/253+7/22.3/14××/23+16/3.125/×2/3+5/64.2922/+111/÷/2152.53/×1/514/3+62.452/3×+13×152/7./197+1/129×5/6281/.4+3/4÷2/329.87/×2116/+1/203.1011×5/–1/5×131250.＋601÷04（5+378）0（64÷4-）532.120-14418+353÷3.34+754×241-60÷5234（5+873÷）（64-×59）359.÷（54-46）563178.1-45÷×5+462204+580-4×26÷218378.217-0÷09（+3×111）（36+61）×（64-5345÷233）.85+148（14+2×80÷26）93.28（4+1）6×5（128-28÷108）4012.0-634×÷1+3854.（15+378）÷64（-×9）5 4.2(6.-8.68×0.55)8÷.53.4.0124.×80.12×÷.844.4（32.1.×52.+5）1÷6（2.）.32×（.51+.2）5÷1.6456-..61÷=4538+7..5-8.573=6.472÷.0.-8.1×2=56-1.9×3-10.34=7.465.（4×.-8.124）×0=68.1.9+×.32×1094..18.0511-.75×0.4-05.749.5.8×（.38-0713）+..423×74.50.32.52（-6+9.78÷3.2）2×.251.55+-581+3+0+978(--56+5)02.57*2--57/(353(-7)*.2/1/()+79/(336/4）5+412.3+465+7989+8(/-)455.396/33(--4-31/15.5556)3.+{39[4x/22x(x83]})579x8.7x/x5(+6)458.112x2(/4+1/2)5299.4(-6+)/100.1^a-3b^23a+(b2-b)a a^3+2=^2ab-b^23-ba2^=a^(a2+b)2b^2-(b+2)=(a+2ba(a^2-b)^2)=(a+2)ba(+)b(ab)2.-(x^2y+2)^^2-4(x^y2+y^2+)4y^=(2x2^+^2-y2)^2y3.x^2+2(x)^+32x(^+2x2)+^2x+2x+=(3^2x2x+^)24(x^2++x)23+=(x^+22+x)3(x^22x++1)=x(2^2x+3)(++x)^124.(a+1)a+2()+(2+1)(aa2)--21a^2+=3+a+2a^2-3a22--21=3a^21-2=(3+a2()-2)a5.x^(2yz+)2^-2y(x-xz(y)+)zy+^2x(-z)^2=[xy+()z-(yxz)-^2=(]xzy+z)2^z^2(=x+y^)2 .3(6+2)^2a+28(+2)a2-0=[(a+23)2]-[(+a)+120=]3a+4((a)+1)2.7(+a)b^-(2b-c)2^a+2^-^c=(2+b)a^2-^2ca+^-2(-cb)^2(a+=bc+()ab-+)+(c+ba-)(c-bac)=(a++-bc(a)+bc++-abc+)=2a+b-c)(a(c)+8x.(x+)1x(^2x+1)-2=(-x^+2x(x)2^+x-1)-2=(^x+2)x2^(-^x+x2)2-=(^2+xx-)2x(2+x^+1=)(+x2)x(1)(-^x+x2+)11./37×4/99-/432.8/9×1/563+1/2731.25×/–629/×34.×854/+1/45.÷6/38–38/÷664.
/7×5/9+37/5×9/ 7.5/2-（3/2+4/5）8.7/8+（1/8+1/9）9.9×/6+5/5610.3/4×/891-/0312.χ1＋8.×.09=7.2(－5χ)9×.0=3.106.4χ-χ=22+4.41817×.5/943/14+12.6×1（/22+3/）1.38×/54+8×115/4.113×/65–5/65.19/7-（2/–71/20116）.59×18/–14×2/71.745×/2516/2+/3×3/184.41×/78–56×/12/15191./73–23/4×/94220.3×29+/13/21./75×/325+/722.33/4×12×3/+16/231/.×52/3+5/624.9/2+21/111/2÷25.5/×31/15+4/32.46×523/+/31×5 27.7/11+192/9×51/628./413+/4÷2/32.987/×21/6+11230./110×1/–51/×5231.50＋16104÷0（5+837）÷06（-445）23.21-04411÷835+33.47345×+-24106÷254（538+73÷）64-9×（）553.9÷5（6-45）46.137-841÷55×+6244205+8-64×20÷12873.812700-（÷93+×11）（131+646×（6）-3554÷32）3885+1.×4（4+210÷28）369（.824+16×）（51-2802÷81）40.120-3864×÷813+415（.5+387÷）64-9（×5）24(..866.-×0.855÷)85.3.4012×4..8÷.02×41.844（.3.2×.512+5.÷1）.（2）36.2（×.5+215.÷1）645..-166.4÷=5.38+.85-7.57=364.7.20.8-1.2÷×5=-611.93-×.43=047.6 .5×（4.-18.24×）0.6=×8.9+1.032×.198.140.5-101.5×7.0-4.574.598×（3.87-..013）4.2×3+.470.52.532（-6+97.8÷2.3）22×.551-.+58+531+90+8-7-(56+)055.-2*7-257(3/3.(57-*)2(//3)1+7/(9+634）/5412.3+45+6897+9/(-84)553.6933-(-/4-5311/.55)563.9+{3[x2/2x(43x)8]}5.798xx75/x4+(6)5.118x2/(4+1222)/5.94+9-60(/1)01.^3-a2^3bab(+a-2)b=a^3+2a2b-^b23^ab^2=-a^(2+2ba-b)2(2^ba)+=(a2+b)a(2^-^2)=(ba+b)(a2+b()-ab)2(x^2+.^2)y^24-y(x^+2y2^)4+y^2= x^(2+y^-22y^2)3.(x2+2x^)2+^(3x^2+2x)x^2++x+2=(3^2+2xx)^+2(x^242+)x+3=x^(2+x2+)(3^x22+x+)1(=^2x+x+23()x+1)^42.(a1)+(a+2)(+a+1)(a-22)-12=a^2+3+2+aa2^2-3a--122=a^32-21=3a+()(2-2)a5.^2(yxz+)^2-x2y(-xz(y+z)+)y2^(-x)^z2[x=y(z)+-(y-zx])2^=xz(+y)z^=2z2(^+y)x2^6.3a+2)^2(+2(a8+2)20-=3[a(2+-)2][a(+)+20]1=(3a4+(a+12)7)(a.+b)^2(b-c)^-+a^22c^-2 =a(+b)^-2^2+a^c2-(bc)^2=-(ab++)(ac+-c)+ba+b(c)-a(-b+)c=(ab+-)ca+b+(+ac-b+c)2(=+abc)-a(c+8)x(x.1+)(x^2+x1)-2-=(^2xx+()x2^x+1-)2-(x^2+=)^x2(x^2-x+-)=(x^2+2x-2()^2xx+1+)=(x2)+(x-)1(^2x++1x)
发布于 2025-01-15 14:52:09
阅读
(0)